Q22·Section B (Part B)·22 of 120Dyadic fractions versus terminating decimalsLet A={pq∈(0,1):p∈N,q=2n for some n∈N∪{0},gcd(p,q)=1},A=\Big\{\tfrac pq\in(0,1):p\in\mathbb N, q=2^n\text{ for some }n\in\mathbb N\cup\{0\}, \gcd(p,q)=1\Big\},A={qp∈(0,1):p∈N,q=2n for some n∈N∪{0},gcd(p,q)=1}, B={pq∈(0,1):p∈N,q=2n5m for some n,m∈N∪{0},gcd(p,q)=1},B=\Big\{\tfrac pq\in(0,1):p\in\mathbb N, q=2^n5^m\text{ for some }n,m\in\mathbb N\cup\{0\}, \gcd(p,q)=1\Big\},B={qp∈(0,1):p∈N,q=2n5m for some n,m∈N∪{0},gcd(p,q)=1}, C={pq∈(0,1):pq has terminating decimal expansion}C=\Big\{\tfrac pq\in(0,1):\tfrac pq\text{ has terminating decimal expansion}\Big\}C={qp∈(0,1):qp has terminating decimal expansion} be subsets of (0,1)(0,1)(0,1). Which of the following statements is true? OptionsAA⊊CA\subsetneq CA⊊C and B⊊CB\subsetneq CB⊊CBA⊊C⊊BA\subsetneq C\subsetneq BA⊊C⊊BCA⊊B⊊CA\subsetneq B\subsetneq CA⊊B⊊CDA⊊B=CA\subsetneq B=CA⊊B=CPick an option to check your answer.Show answerShow solution Report a problem with this question← Q21All questionsQ23 →Keyboard: A–D answer · S solution · ←/→ previous/next