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Q42Section B (Part B)42 of 120

Sum of reciprocals of eigenvalues of a Sturm-Liouville problem

Let (λn)n∈N(\lambda_n)_{n\in\mathbb N} be the sequence of eigenvalues of the Sturm–Liouville problem

ddx(xdydx)+λxy=0,1<x<e2π,y(1)=0,y(e2π)=0.\frac d{dx}\Big(x\frac{dy}{dx}\Big)+\frac\lambda xy=0,\quad1<x<e^{2\pi},\qquad y(1)=0, y(e^{2\pi})=0.

Then ∑n=1∞1λn\displaystyle\sum_{n=1}^\infty\frac1{\lambda_n} is equal to

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