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Q46Section B (Part B)46 of 120

Extremal of a quadratic functional with fixed end values

Let y(x)y(x) be the extremal of the functional

J[y]=∫0π/4((y′)2−4y2+2xy) dxJ[y]=\int_0^{\pi/4}\big((y')^2-4y^2+2xy\big)\,dx

subject to y(0)=0y(0)=0, y ⁣(π4)=1y\!\left(\tfrac\pi4\right)=1. Then y(x)y(x) is equal to

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