If the probability density function of the normal distribution of X is f(x)=kexp(-frac18 x^2+2x), -infty<x<infty, then the mean and variance of the distribution are respectively:

Q38Section I (Objective (Q1–Q80))38 of 80

Distribution Theory — mean and variance from a normal exponent

If the probability density function of the normal distribution of X is $f(x)=k\exp\left(-\frac18 x^2+2x\right)$ , $-\infty<x<\infty$ , then the mean and variance of the distribution are respectively:

Pick an option to check your answer. In a mock test a wrong answer here costs 0.83 mark.

Keyboard: A–D answer · S solution · ←/→ previous/next