Let X and Y have joint probability mass function P(X=x, Y=y)=frace^-2x!(y-x)!;quad x=0,1,2,…,y and y=1,2,3,… With reference to the above, consider the following statements: I. Y follows Poisson distribution with parameter 1/2. II. E(X)=1 Which of the statements given above is/are correct?

Q33Section I (Objective (Q1–Q80))33 of 79

Distribution Theory — marginal and mean of a Poisson-Binomial mixture

Let $X$ and $Y$ have joint probability mass function

$P(X=x, Y=y)=\frac{e^{-2}}{x!(y-x)!};\quad x=0,1,2,…,y \text{ and } y=1,2,3,…$

With reference to the above, consider the following statements:

$\text{I. } Y \text{ follows Poisson distribution with parameter } 1/2.$

$\text{II. } E(X)=1$

Which of the statements given above is/are correct?

Pick an option to check your answer. In a mock test a wrong answer here costs 0.83 mark.

Keyboard: A–D answer · S solution · ←/→ previous/next