Let k 0 be a constant such that pdf of X is given by f(x) = begincases kx(1-x), & 0 < x < 1 0, & elsewhere endcases. What is the value of E(X)?

Q8Section I (Objective (Q1–Q80))8 of 80

Distribution Theory — mean of a quadratic density

Let $k > 0$ be a constant such that pdf of $X$ is given by $f(x) = \begin{cases} kx(1-x), & 0 < x < 1 \ 0, & \text{elsewhere} \end{cases}$ . What is the value of $\mathbb{E}(X)$ ?

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