Q56·Section I (Objective (Q1–Q80))·56 of 80Design of Experiments — completing an ANOVA tableIn the following Analysis of Variance Table, few entries are missing. Source of variationDegrees of freedomSum of squaresVariance ratioTreatment416⋅42⋅05 Varietyx287 Erroryz Total15\begin{array}{c|c|c|c} \text{Source of variation} & \text{Degrees of freedom} & \text{Sum of squares} & \text{Variance ratio} \\\hline \text{Treatment} & 4 & 16\cdot 4 & 2\cdot 05 \ \text{Variety} & x & 28 & 7 \ \text{Error} & y & z & \ \text{Total} & 15 & & \end{array}Source of variationTreatmentDegrees of freedom4Sum of squares16⋅4Variance ratio2⋅05 Varietyx287 Erroryz Total15 What are the values of xxx, yyy and zzz respectively? OptionsA4,9,184, 9, 184,9,18B2,9,162, 9, 162,9,16C9,2,189, 2, 189,2,18D2,9,182, 9, 182,9,18Pick an option to check your answer. In a mock test a wrong answer here costs 0.83 mark.Show answerShow solution Report a problem with this question← Q55All questionsQ57 →Keyboard: A–D answer · S solution · ←/→ previous/next