If the joint p.d.f. of two random variables X and Y is f(x,y)=begincases21/2x^2y, & x^2le y, 0<x<1 0, & otherwiseendcases then the value of P(Xge Y) is

Q19Section I (Objective (Q1–Q80))19 of 80

Probability — a probability from a continuous joint pdf

If the joint p.d.f. of two random variables $X$ and $Y$ is

$f(x,y)=\begin{cases}\dfrac{21}{2}x^2y, & x^2\le y, 0<x<1\ 0, & \text{otherwise}\end{cases}$

then the value of $P(X\ge Y)$ is

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