Q1·Section A (Section A)·1 of 15Eigenvector of a triangular matrix with a repeated eigenvalueAn eigenvector of the matrix M=(210021002)M=\begin{pmatrix}2&1&0\\0&2&1\\0&0&2\end{pmatrix}M=200120012 is OptionsA(100)\begin{pmatrix}1\\0\\0\end{pmatrix}100B(010)\begin{pmatrix}0\\1\\0\end{pmatrix}010C(001)\begin{pmatrix}0\\0\\1\end{pmatrix}001D(222)\begin{pmatrix}2\\2\\2\end{pmatrix}222Pick an option to check your answer.Show answerShow solution Report a problem with this questionAll questionsQ2 →Keyboard: A–D answer · S solution · ←/→ previous/next