Q1·Section A (Section A)·1 of 60Rank of a four by four matrix with dependent rowsLet P=[1202−1−21112−3−712−2−4].P=\begin{bmatrix}1&2&0&2\\-1&-2&1&1\\1&2&-3&-7\\1&2&-2&-4\end{bmatrix}.P=1−1112−22201−3−221−7−4. Then rank of PPP equals OptionsA444B333C222D111Pick an option to check your answer.Show answerShow solution Report a problem with this questionAll questionsQ2 →Keyboard: A–D answer · S solution · ←/→ previous/next