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Q6Section A (Section A)6 of 60

Probability of an event from conditional probabilities of independent events

Let EE and FF be two independent events with P(E∣F)+P(F∣E)=1P(E|F)+P(F|E)=1, P(E∩F)=29P(E\cap F)=\frac29 and P(F)<P(E)P(F)<P(E). Then P(E)P(E) equals

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