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Q44Section C (Section C)44 of 60

Conditional probability from a pmf with squares

Let XX and YY be discrete random variables with the joint probability mass function p(x,y)=125(x2+y2)p(x,y)=\frac1{25}(x^2+y^2), if x=1,2x=1,2; y=0,1,2y=0,1,2. Then P(Y=1∣X=1)P(Y=1|X=1) equals __________________

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