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Q19Section A (Section A)19 of 60

Probability of E without F or G

Let E,FE,F and GG be any three events with P(E)=0.3P(E)=0.3, P(F∣E)=0.2P(F|E)=0.2, P(G∣E)=0.1P(G|E)=0.1 and P(F∩G∣E)=0.05P(F\cap G|E)=0.05. Then P(E−(F∪G))P(E-(F\cup G)) equals

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