Q4·Section A (Section A)·4 of 60Linear map given on a basis of R2Let T:R2→R2T:\mathbb R^2\to\mathbb R^2T:R2→R2 be a linear transformation such that T([12])=[10]T\left(\begin{bmatrix}1\\2\end{bmatrix}\right)=\begin{bmatrix}1\\0\end{bmatrix}T([12])=[10] and T([21])=[01]T\left(\begin{bmatrix}2\\1\end{bmatrix}\right)=\begin{bmatrix}0\\1\end{bmatrix}T([21])=[01]. Suppose that [3−2]=α[12]+β[21]\begin{bmatrix}3\\-2\end{bmatrix}=\alpha\begin{bmatrix}1\\2\end{bmatrix}+\beta\begin{bmatrix}2\\1\end{bmatrix}[3−2]=α[12]+β[21] and T([3−2])=[ab]T\left(\begin{bmatrix}3\\-2\end{bmatrix}\right)=\begin{bmatrix}a\\b\end{bmatrix}T([3−2])=[ab]. Then α+β+a+b\alpha+\beta+a+bα+β+a+b equals OptionsA23\dfrac2332B43\dfrac4334C53\dfrac5335D73\dfrac7337Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q3All questionsQ5 →Keyboard: A–D answer · S solution · ←/→ previous/next