Q16·Section A (Section A)·16 of 60Polar double integral over a shifted discThe value of the integral ∫02∫02x−x2x2+y2 dy dx\int_{0}^{2}\int_{0}^{\sqrt{2x-x^{2}}}\sqrt{x^{2}+y^{2}}\,dy\,dx∫02∫02x−x2x2+y2dydx is OptionsA179\dfrac{17}{9}917B169\dfrac{16}{9}916C149\dfrac{14}{9}914D139\dfrac{13}{9}913Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q15All questionsQ17 →Keyboard: A–D answer · S solution · ←/→ previous/next