Variance of a normal sample variance

Let $X_{1},X_{2},…,X_{10}$ be a random sample from $N(1,2)$ distribution. If $$\bar{X}=\frac{1}{10}\sum_{i=1}^{10}X_{i}\quad\text{and}\quad S^{2}=\frac{1}{9}\sum_{i=1}^{10}(X_{i}-\bar{X})^{2},$$ then $\operatorname{Var}(S^{2})$ equals