Q1·Section A (Section A)·1 of 60Geometric mean limit via Riemann sumThe value of the limit limn→∞((1+1n)(1+2n)⋯(1+nn))1n\lim_{n\to\infty}\left(\left(1+\frac{1}{n}\right)\left(1+\frac{2}{n}\right)\cdots\left(1+\frac{n}{n}\right)\right)^{\frac{1}{n}}n→∞lim((1+n1)(1+n2)⋯(1+nn))n1 is equal to OptionsAeeeB1e\dfrac{1}{e}e1C3e\dfrac{3}{e}e3D4e\dfrac{4}{e}e4Pick an option to check your answer.Show answerShow solution Report a problem with this questionAll questionsQ2 →Keyboard: A–D answer · S solution · ←/→ previous/next