Q3·Section A (Section A)·3 of 60Exponentials against a cosineThe value of the limit limx→0e−3x−ex+4x5(1−cosx)\lim_{x\to 0}\frac{e^{-3x}-e^{x}+4x}{5(1-\cos x)}x→0lim5(1−cosx)e−3x−ex+4x is equal to OptionsA111B000C25\dfrac{2}{5}52D85\dfrac{8}{5}58Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q2All questionsQ4 →Keyboard: A–D answer · S solution · ←/→ previous/next