Q11·Section A (Section A)·11 of 60Limit of a Riemann sumlimn→∞6n+2{(2+1n)2+(2+2n)2+⋯+(2+n−1n)2}\lim_{n\to\infty} \frac{6}{n+2} \left\{\left(2+\frac{1}{n}\right)^2 + \left(2+\frac{2}{n}\right)^2 + \dots + \left(2+\frac{n-1}{n}\right)^2\right\}limn→∞n+26{(2+n1)2+(2+n2)2+⋯+(2+nn−1)2} equals OptionsA38B36C32D30Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q10All questionsQ12 →Keyboard: A–D answer · S solution · ←/→ previous/next