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Q53Section C (Section C)53 of 60

Unit eigenvector of symmetric matrix

Let A=(1−12 −101 211)A=\begin{pmatrix} 1 & -1 & 2 \ -1 & 0 & 1 \ 2 & 1 & 1 \end{pmatrix} and let (x1 x2 x3)\begin{pmatrix} x_1 \ x_2 \ x_3 \end{pmatrix} be an eigenvector corresponding to the smallest eigenvalue of AA, satisfying x12+x22+x32=1x_1^2+x_2^2+x_3^2=1. Then the value of ∣x1∣+∣x2∣+∣x3∣|x_1|+|x_2|+|x_3| equals __________ (round off to 22 decimal places)

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