Q26·Section A (Section A)·26 of 60Volume of truncated cylinderThe volume of the region R={(x,y,z)∈R×R×R:x2+y2≤4,0≤z≤4−y}R=\{(x, y, z)\in\mathbb{R}\times\mathbb{R}\times\mathbb{R} : x^2+y^2 \le 4, 0 \le z \le 4-y\}R={(x,y,z)∈R×R×R:x2+y2≤4,0≤z≤4−y} is OptionsA16π−1616\pi - 1616π−16B16π16\pi16πC8π8\pi8πD16π+416\pi+416π+4Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q25All questionsQ27 →Keyboard: A–D answer · S solution · ←/→ previous/next