Q3·Section A (Section A)·3 of 60Sum of inverse and inverse adjointLet A=(a0 cd)A=\begin{pmatrix}a&0\ c&d\end{pmatrix}A=(a0 cd) be a real matrix, where ad=1ad=1ad=1 and c≠0c\neq 0c=0. If A−1+(adj A)−1=(αβ γδ),A^{-1}+(\mathrm{adj}\,A)^{-1}=\begin{pmatrix}\alpha&\beta\ \gamma&\delta\end{pmatrix},A−1+(adjA)−1=(αβ γδ), then (α,β,γ,δ)(\alpha,\beta,\gamma,\delta)(α,β,γ,δ) is equal to OptionsA(a+d, 0, 0, a+d)(a+d,\,0,\,0,\,a+d)(a+d,0,0,a+d)B(a+d, 0, c, a+d)(a+d,\,0,\,c,\,a+d)(a+d,0,c,a+d)C(a, 0, 0, d)(a,\,0,\,0,\,d)(a,0,0,d)D(a, 0, c, d)(a,\,0,\,c,\,d)(a,0,c,d)Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q2All questionsQ4 →Keyboard: A–D answer · S solution · ←/→ previous/next