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Competitive Stats
Q52Section C (Section C)52 of 60

Integral of radius over a circular sector

The value of the integral ∫02∫x8−x23x2+y28 π dy dx\int_0^2\int_x^{\sqrt{8-x^2}}\frac{3\sqrt{x^2+y^2}}{\sqrt{8}\,\pi}\,dy\,dx is equal to __________ (answer in integer)

Numerical answer: type the number (no options).

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