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Q43Section C (Section C)43 of 60

Second-order difference of a sine

Let f(x)=xsin⁡(π2x),x>0.f(x)=x\sin\left(\frac{\pi}{2x}\right),\quad x>0. Then lim⁡h→01π2h2[3f(1)−2f(1+h)−f(1−2h)]\lim_{h\to 0}\frac{1}{\pi^2 h^2}\bigl[3f(1)-2f(1+h)-f(1-2h)\bigr] is equal to __________ (round off to 2 decimal places)

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