Q48·Section II (Mathematics)·48 of 84∣y12−y22∣≤2b∣y1−y2∣|y_1^2-y_2^2|\le2b|y_1-y_2|∣y12−y22∣≤2b∣y1−y2∣ needs ∣y∣≤b|y|\le b∣y∣≤bThe function f(x,y)=y2f(x,y)=y^2f(x,y)=y2 satisfies a Lipschitz condition on: OptionsA{(x,y)∣∣x∣<∞,∣y∣<∞}\{(x,y)\mid|x|<\infty, |y|<\infty\}{(x,y)∣∣x∣<∞,∣y∣<∞}B{(x,y)∣∣x∣≤a,∣y∣<∞,(a>0)}\{(x,y)\mid|x|\le a, |y|<\infty, (a>0)\}{(x,y)∣∣x∣≤a,∣y∣<∞,(a>0)}C{(x,y)∣−7≤x≤10,∣y∣<∞}\{(x,y)\mid-7\le x\le10, |y|<\infty\}{(x,y)∣−7≤x≤10,∣y∣<∞}D{(x,y)∣∣x∣≤a,∣y∣≤b,(a,b>0)}\{(x,y)\mid|x|\le a, |y|\le b, (a,b>0)\}{(x,y)∣∣x∣≤a,∣y∣≤b,(a,b>0)}Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q47All questionsQ49 →Keyboard: A–D answer · S solution · ←/→ previous/next