Q113·Section III (Statistics)·113 of 145Reading "se(β^,γ^)\mathrm{se}(\hat\beta,\hat\gamma)se(β^,γ^)" as the s.e. of β^γ^\hat\beta\hat\gammaβ^γ^ (delta method)Consider logyi=α+βxi+γzi+εi\log y_i=\alpha+\beta x_i+\gamma z_i+\varepsilon_ilogyi=α+βxi+γzi+εi with β^=1.5\hat\beta=1.5β^=1.5, se(β^)=0.75\mathrm{se}(\hat\beta)=0.75se(β^)=0.75, γ^=4\hat\gamma=4γ^=4, se(γ^)=0.75\mathrm{se}(\hat\gamma)=0.75se(γ^)=0.75 and Cov(β^,γ^)=0.2\operatorname{Cov}(\hat\beta,\hat\gamma)=0.2Cov(β^,γ^)=0.2. What will be se(β^,γ^)\mathrm{se}(\hat\beta,\hat\gamma)se(β^,γ^)? OptionsA0.5525B2.25C1.50D3.56Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q112All questionsQ114 →Keyboard: A–D answer · S solution · ←/→ previous/next