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Q46Section II (Mathematics)46 of 145

Orthogonal surfaces: z(3z+1)(p+q)=x+yz(3z+1)(p+q)=x+y, through the given circle

Equation of the surface which intersects the surfaces of the system z(x+y)=c(3z+1)z(x+y)=c(3z+1) orthogonally and which passes through the circle x2+y2=1x^2+y^2=1, z=1z=1 is:

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