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Q51Section II (Mathematics)51 of 145

∑d∣nμ(d)=0\sum_{d\mid n}\mu(d)=0 for n>1n>1

If μ(n)\mu(n) denotes the M"obius function, then ∑d∣1000μ(d)\sum_{d\mid1000}\mu(d) is equal to:

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