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Q64Section II (Mathematics)64 of 145

Substitute x=et2wx=e^{t^2}w: then w=1+∫0tww=1+\int_0^tw, so w=etw=e^t

Solution of the integral equation x(t)=et2+∫0tet2−s2x(s) dsx(t)=e^{t^2}+\int_0^te^{t^2-s^2}x(s)\,ds with the help of resolvent kernel method is:

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