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Q67Section II (Mathematics)67 of 145

Two Euler steps: 0→0.1→0.190\to0.1\to0.19

For the initial value problem y′=1−yy'=1-y, y(0)=0y(0)=0, the value of y(0.2)y(0.2) by Euler's method (taking h=0.1h=0.1) is:

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