Q7·Section II (Mathematics)·7 of 145d'Alembert-type solutions f(x+2y)+g(x−2y)f(x+2y)+g(x-2y)f(x+2y)+g(x−2y) satisfy uyy=4uxxu_{yy}=4u_{xx}uyy=4uxxIf u=f(x+2y)+g(x−2y)u=f(x+2y)+g(x-2y)u=f(x+2y)+g(x−2y), then: OptionsA4∂2u∂x2=∂2u∂y24\dfrac{\partial^2u}{\partial x^2}=\dfrac{\partial^2u}{\partial y^2}4∂x2∂2u=∂y2∂2uB∂2u∂x2=4∂2u∂y2\dfrac{\partial^2u}{\partial x^2}=4\dfrac{\partial^2u}{\partial y^2}∂x2∂2u=4∂y2∂2uC2∂2u∂x2=∂2u∂y22\dfrac{\partial^2u}{\partial x^2}=\dfrac{\partial^2u}{\partial y^2}2∂x2∂2u=∂y2∂2uD∂2u∂x2=2∂2u∂y2\dfrac{\partial^2u}{\partial x^2}=2\dfrac{\partial^2u}{\partial y^2}∂x2∂2u=2∂y2∂2uPick an option to check your answer.Show answerShow solution Report a problem with this question← Q6All questionsQ8 →Keyboard: A–D answer · S solution · ←/→ previous/next