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Q85Section III (Statistics)85 of 145

The average winnings settle near m<m/2m<m/2

Let XnX_n be the amount that someone wins on a trial nn, in a game of chance, with XiX_i independent, each with mean m<0m<0 and variance σ2\sigma^2. Then, as n→∞n\to\infty, P(X1+⋯+Xnn<m2)P\bigl(\frac{X_1+\dots+X_n}n<\frac m2\bigr) will tend to:

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