Q91·Section III (Statistics)·91 of 145Density x+yx+yx+y on the unit square: Cov(X,Y)=−1144\operatorname{Cov}(X,Y)=-\tfrac1{144}Cov(X,Y)=−1441Let (X,Y)(X,Y)(X,Y) have joint density f(x,y)=x+yf(x,y)=x+yf(x,y)=x+y, 0<x<10<x<10<x<1, 0<y<10<y<10<y<1. Then: OptionsAX and Y are uncorrelatedBX and Y have the same mean but different varianceCX and Y are negatively correlatedDX and Y are independentPick an option to check your answer.Show answerShow solution Report a problem with this question← Q90All questionsQ92 →Keyboard: A–D answer · S solution · ←/→ previous/next