Q97·Section III (Statistics)·97 of 145U(θ,2θ)U(\theta,2\theta)U(θ,2θ): the likelihood falls in θ\thetaθ on [X(n)/2,X(1)][X_{(n)}/2,X_{(1)}][X(n)/2,X(1)]Let X1,…,XnX_1,\dots,X_nX1,…,Xn be iid U(θ,2θ)U(\theta,2\theta)U(θ,2θ). The maximum likelihood estimator of θ\thetaθ is: OptionsAX(n)X_{(n)}X(n)BX(n)/2X_{(n)}/2X(n)/2CX(1)X_{(1)}X(1)DX(1)+X(n)2\dfrac{X_{(1)}+X_{(n)}}22X(1)+X(n)Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q96All questionsQ98 →Keyboard: A–D answer · S solution · ←/→ previous/next