Q17·Section II (Mathematics)·17 of 84e−1/xe^{-1/x}e−1/x glued to 0: smooth at the origin but not analyticLet f(x)=e−1/xf(x)=e^{-1/x}f(x)=e−1/x if x>0x>0x>0, and f(x)=0f(x)=0f(x)=0 if x≤0x\le0x≤0. Then: OptionsAf(x)f(x)f(x) is not continuousBf(x)f(x)f(x) is continuous but not C1C^1C1Cf(x)f(x)f(x) is C1C^1C1 but not C∞C^\inftyC∞Df(x)f(x)f(x) is C∞C^\inftyC∞ but not analyticPick an option to check your answer.Show answerShow solution Report a problem with this question← Q16All questionsQ18 →Keyboard: A–D answer · S solution · ←/→ previous/next