Q2·Section I (General (compulsory))·2 of 84Integrating the geometric series ∑(−1)kx2k\sum(-1)^kx^{2k}∑(−1)kx2k gives tan−1x\tan^{-1}xtan−1xThe series x−x33+x55−x77+⋯x-\dfrac{x^3}3+\dfrac{x^5}5-\dfrac{x^7}7+\cdotsx−3x3+5x5−7x7+⋯, ∣x∣<1|x|<1∣x∣<1, represents the function: OptionsAtan−1x\tan^{-1}xtan−1xBtanx\tan xtanxCsin−1x\sin^{-1}xsin−1xDlog(1+x)\log(1+x)log(1+x)Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q1All questionsQ3 →Keyboard: A–D answer · S solution · ←/→ previous/next