Q25·Section II (Mathematics)·25 of 84logx/x\log x/xlogx/x peaks at x=ex=ex=e with value 1/e1/e1/eThe maximum value of logxx\dfrac{\log x}xxlogx, x>0x>0x>0 is: OptionsAeeeB1e\dfrac1ee1Ce+1ee+\dfrac1ee+e1D−1e+e-\dfrac1e+e−e1+ePick an option to check your answer.Show answerShow solution Report a problem with this question← Q24All questionsQ26 →Keyboard: A–D answer · S solution · ←/→ previous/next