Q7·Section I (General (compulsory))·7 of 84rank(AAt)=rankA\operatorname{rank}(AA^t)=\operatorname{rank} Arank(AAt)=rankA for real matricesIf A=(12303−20−64),A=\begin{pmatrix}1&2&3\\0&3&-2\\0&-6&4\end{pmatrix},A=10023−63−24, then the rank of the matrix AAtAA^tAAt is: OptionsA1B2C3D0Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q6All questionsQ8 →Keyboard: A–D answer · S solution · ←/→ previous/next