$Y\mid X=5$ has mean 10 and s.d. $5\sqrt{1-\rho^2}$; the sign of $\rho$ is not identified

Given $(X,Y)\sim N_2(5,10,1,25,\rho)$ and $P[4<Y<16\mid X=5]=0.954$, then $\rho$ is equal to (it is given that $\frac1{\sqrt{2\pi}}\int_0^2e^{-z^2/2}dz=0.477$):