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Q15Section II (Mathematics)15 of 145

Ratio test: the 2n2^n in the denominator sets the radius to 2

The radius of convergence of the power series ∑n=0∞zn(n2+1)2n\displaystyle\sum_{n=0}^\infty\frac{z^n}{(n^2+1)2^n} is:

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