Let alpha:(frac12,2)toR^3 be defined by alpha(t)=(t,-t,t^3). Then the torsion of alpha at t=1 is:

Q57Section II (Mathematics)57 of 145

A curve lying in the plane $x+y=0$ has zero torsion

Let $\alpha:\bigl(\frac12,2\bigr)\to\mathbb{R}^3$ be defined by $\alpha(t)=(t,-t,t^3)$ . Then the torsion of $\alpha$ at $t=1$ is:

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