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Q68Section II (Mathematics)68 of 145

Δ5u0=∑k(−1)5−k(5k)uk\Delta^5u_0=\sum_k(-1)^{5-k}\binom5ku_k

If u0=1u_0=1, u1=5u_1=5, u2=8u_2=8, u3=3u_3=3, u4=7u_4=7, u5=0u_5=0, then the value of Δ5u0\Delta^5u_0 is:

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