Q9·Section II (Mathematics)·9 of 145x2+y2+z2=(x+y+z)2−2(xy+yz+zx)x^2+y^2+z^2=(x+y+z)^2-2(xy+yz+zx)x2+y2+z2=(x+y+z)2−2(xy+yz+zx)The functions f1(x,y,z)=x+y+zf_1(x,y,z)=x+y+zf1(x,y,z)=x+y+z, f2(x,y,z)=xy+yz+zxf_2(x,y,z)=xy+yz+zxf2(x,y,z)=xy+yz+zx, f3(x,y,z)=x2+y2+z2f_3(x,y,z)=x^2+y^2+z^2f3(x,y,z)=x2+y2+z2: OptionsAare functionally independent on R3∖{x-axis}\mathbb{R}^3\setminus\{x\text{-axis}\}R3∖{x-axis}Bare functionally independent on the set {(x,y,z)∈R3:x>0}\{(x,y,z)\in\mathbb{R}^3:x>0\}{(x,y,z)∈R3:x>0}Care functionally independent on the set {(x,y,z)∈R3:x>0,y>0,z>0}\{(x,y,z)\in\mathbb{R}^3:x>0,y>0,z>0\}{(x,y,z)∈R3:x>0,y>0,z>0}Dare functionally dependent on R3\mathbb{R}^3R3Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q8All questionsQ10 →Keyboard: A–D answer · S solution · ←/→ previous/next