Q104·Section III (Statistics)·104 of 190P(A∣B)=P(B)P(A\mid B)=P(B)P(A∣B)=P(B) forces P(B)2=P(A∩B)≤P(A)P(B)^2=P(A\cap B)\le P(A)P(B)2=P(A∩B)≤P(A)If P(A∣B)=P(B)P(A\mid B)=P(B)P(A∣B)=P(B), then: OptionsAP(B∣A)=P(A)P(B\mid A)=P(A)P(B∣A)=P(A)BA and B are independent eventsCP2(A)≤P(B)P^2(A)\le P(B)P2(A)≤P(B)DP2(B)≤P(A)P^2(B)\le P(A)P2(B)≤P(A)Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q103All questionsQ105 →Keyboard: A–D answer · S solution · ←/→ previous/next