Let f(z)=csc(tfrac1z-1) for zneq1, zinmathbf C. Then at the point z=1, f has:

Q20Section II (Mathematics)20 of 190

Poles of $\csc(1/(z-1))$ accumulate at $z=1$ itself

Let $f(z)=\csc\bigl(\tfrac1{z-1}\bigr)$ for $z\neq1, z\in\mathbf C$ . Then at the point $z=1$ , f has:

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