Composing two Jacobians via the chain rule

Let $f:\mathbb{R}^3\to\mathbb{R}^2$ be defined by the equation $f(x,y,z)=(xy,y+z)$ and $g:\mathbb{R}^2\to\mathbb{R}^2$ be defined as $g(x,y)=(x+y,y)$. Then the derivative $D(g\circ f)(0,0,0)=$