Reading a joint pmf table directly to find $P[X=2Y]$

Let the joint distribution of (X, Y) be specified by the table with $X\in\{1,2,3,4\}$ and $Y\in\{1,2\}$: row $Y{=}1$ gives $1/16, 3/32, 1/8, 5/32$ and row $Y{=}2$ gives $3/32, 1/8, 5/32, 3/16$ (for $X=1,2,3,4$ respectively). Then $P[X=2Y]$ is: