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Q176Section III (Statistics)176 of 190

Marginalizing a mixed initial distribution through one step of the transition matrix

Let {Xn}0∞\{X_n\}_0^\infty be a Markov chain with P[X0=0]=P[X0=1]=1/4P[X_0=0]=P[X_0=1]= 1/4 and P[X0=2]=1/2P[X_0=2]=1/2. The t.p.m. is given by P=(1/21/31/601/32/31/201/2)P=\left(\begin{smallmatrix}1/2&1/3&1/6\\0&1/3&2/3\\1/2&0&1/2\end{smallmatrix}\right) (rows/columns indexed 0,1,20,1,2). Then P[X1=1]P[X_1=1] is given by:

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