Q19·Section II (Mathematics)·19 of 190Extracting a residue from the Laurent series of cos(1/z)\cos(1/z)cos(1/z)The value of the integral 12πi∫∣z∣=1z3cos(1/z) dz\dfrac1{2\pi i}\displaystyle\int_{|z|=1}z^3\cos(1/z)\,dz2πi1∫∣z∣=1z3cos(1/z)dz is: OptionsA0B1C−1/6-1/6−1/6D1/241/241/24Pick an option to check your answer.Show answerShow solution Report a problem with this question← Q18All questionsQ20 →Keyboard: A–D answer · S solution · ←/→ previous/next