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Q60Section II (Mathematics)60 of 190

Two components of an open disc each, regardless of gap size or how the split arises, are all homeomorphic

Let X={(x,y)∈R2:x2+y2<1}∪{(x,y)∈R2:(x−2)2+y2<1}X=\{(x,y)\in\mathbb{R}^2:x^2+y^2<1\}\cup\{(x,y)\in\mathbb{R}^2:(x-2)^2+y^2<1\} and Y={(x,y)∈R2:x2+y2<1}∪{(x,y)∈R2:(x−3)2+y2<1}Y=\{(x,y)\in\mathbb{R}^2:x^2+y^2<1\}\cup\{(x,y)\in\mathbb{R}^2:(x-3)^2+y^2<1\} and Z={(x,y)∈R2:x2+y2<1,x≠0}Z=\{(x,y)\in\mathbb{R}^2:x^2+y^2<1, x\neq0\} be subspaces of the Euclidean space R2\mathbb{R}^2. Then:

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